mathematica如何计算复杂三角函数积分 - MATLAB爱好者论坛-LabFans.com

xwcheng · 2009-08-10, 15:17

S = 0.015; Z = 1.200; SE = 0.017; a0 =
45*Pi/180; P0 = 500000; \[Mu] = 0.19; k = 5; B = 0.800; F = 10000000;
ae = ArcCos[(Z - SE + S)/Z];
m = ((1 + S/Z - Cos[x])*Cos[x])^k;
n = 1 - 5*Z/(4*(SE - S));
nn = 1 - Z/(SE - S);
p = Z/(4*(SE - S))
fs[y_] = Integrate[
Sin[y]/((Cos[y] + S*Cos[y]/Z - (Cos[y])^2))^k, {y, 0, x}]

carlusst · 2010-01-07, 13:53

mathematica 有内置的SinIntegrate CosIntegrate等函数可直接使用

2009-08-10, 15:17	#1
xwcheng 初级会员注册日期: 2008-09-10 年龄: 61 帖子: 4 声望力: 0	mathematica如何计算复杂三角函数积分 S = 0.015; Z = 1.200; SE = 0.017; a0 = 45Pi/180; P0 = 500000; \[Mu] = 0.19; k = 5; B = 0.800; F = 10000000; ae = ArcCos[(Z - SE + S)/Z]; m = ((1 + S/Z - Cos[x])Cos[x])^k; n = 1 - 5Z/(4(SE - S)); nn = 1 - Z/(SE - S); p = Z/(4(SE - S)) fs[y_] = Integrate[ Sin[y]/((Cos[y] + SCos[y]/Z - (Cos[y])^2))^k, {y, 0, x}]

2010-01-07, 13:53	#2
carlusst 初级会员注册日期: 2008-12-05 年龄: 54 帖子: 2 声望力: 0	回复: mathematica如何计算复杂三角函数积分 mathematica 有内置的SinIntegrate CosIntegrate等函数可直接使用