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#1 |
初级会员
注册日期: 2011-02-13
帖子: 1
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求速度vv最大时(此时角度e=90°),a与b的关系,
clc;clear; syms a b e o p g m H1 H2 v u V0 o=atan(b/a*sqrt(tan(e)));%o和e是角度 pretty(o) %p=1/(a*b/(a*a*(sin(o))^2+b*b*(cos(o))^2)^1.5); p=1/(a*b/(a*a*(sin(atan(b/a*sqrt(tan(e)))))^2+b*b*(cos(atan(b/a*sqrt(tan(e)))))^2)^1.5) pretty(p) vv=dsolve('g*(cos(e)-u*sin(e))-(H1/m*v+H2/m*v*v)-u*v*v/p=v/p*Dv','v(0)=V0','e'); %vv=dsolve('Dv=p*g *(cos(e)-u*sin(e))-v*u','v(0)=V0','e'); %pretty(vv) f=inline(vv,'e') vab=f(pi/2); dva=diff(vab,a); a=solve(dva); pretty(a) 计算结果是 Warning: Explicit solution could not be found. > In dsolve at 101 In quxian at 19 f = Inline function: f(e) = [] Warning: List of equations is empty. > In solve at 70 In quxian at 25 +--+ +--+ |
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#2 |
初级会员
注册日期: 2009-10-11
住址: 天津
帖子: 8
声望力: 0 ![]() |
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/ 1/2 \
| b tan(e) | atan| ----------- | \ a / p = (b^2/((b^2*tan(e))/a^2 + 1) + (b^2*tan(e))/((b^2*tan(e))/a^2 + 1))^(3/2)/(a*b) 3 - / 2 2 \2 | b b tan(e) | | ------------- + ------------- | | 2 2 | | b tan(e) b tan(e) | | --------- + 1 --------- + 1 | | 2 2 | \ a a / ---------------------------------- a b Warning: Explicit solution could not be found. > In dsolve at 101 f = Inline function: f(e) = [] Warning: List of equations is empty. > In solve at 70 +--+ |
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