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#1 |
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注册日期: 2008-06-10
年龄: 45
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[x,f,exitflag,output,lambda,grad,hessian]=fmincon('fun',x0,[],[],[],[],lb,ub,'confun',options)
运行程序后,各步迭代结果和输出信息如下: Warning: Large-scale (trust region) method does not currently solve this type of problem, switching to medium-scale (line search). Optimization terminated: magnitude of search direction less than 2*options.TolX and maximum constraint violation is less than options.TolCon. No active inequalities x = Columns 1 through 9 0.9959 0.9838 0.9631 0.9331 0.8926 0.8390 0.7666 0.6672 0.5234 Column 10 0.6607 f = 0.3315 exitflag = 4 output = iterations: 32 funcCount: 628 stepsize: 0.5000 algorithm: 'medium-scale: SQP, Quasi-Newton, line-search' firstorderopt: 707.1440 cgiterations: [] message: [1x142 char] lambda = lower: [10x1 double] upper: [10x1 double] eqlin: [0x1 double] eqnonlin: [0x1 double] ineqlin: [0x1 double] ineqnonlin: [10x1 double] grad = -0.0654 705.2744 -0.0434 -0.0890 0.0762 -0.5614 707.1440 11.7971 11.5717 -0.8764 hessian = 1.0e+013 * Columns 1 through 9 0.2866 0.1472 -0.0305 0.0639 0.1033 0.7275 0.6362 -0.0483 -0.2287 0.1472 0.1936 -0.0007 0.1433 -0.0459 -0.0338 0.1564 0.1402 0.1371 -0.0305 -0.0007 0.0084 0.0121 -0.0411 -0.1747 -0.1436 0.0499 0.0802 0.0639 0.1433 0.0121 0.1249 -0.0958 -0.2876 -0.0987 0.1792 0.2227 0.1033 -0.0459 -0.0411 -0.0958 0.2149 0.8495 0.6647 -0.2839 -0.4223 0.7275 -0.0338 -0.1747 -0.2876 0.8495 3.9221 2.9639 -1.0251 -1.8359 0.6362 0.1564 -0.1436 -0.0987 0.6647 2.9639 2.5616 -0.7417 -1.2689 -0.0483 0.1402 0.0499 0.1792 -0.2839 -1.0251 -0.7417 0.4328 0.5823 -0.2287 0.1371 0.0802 0.2227 -0.4223 -1.8359 -1.2689 0.5823 0.9890 -0.3590 0.3887 0.1251 0.4779 -0.6865 -3.1089 -1.8629 0.9809 1.6688 Column 10 -0.3590 0.3887 0.1251 0.4779 -0.6865 -3.1089 -1.8629 0.9809 1.6688 3.3615 请教各位高手: 这个程序结果不对吧? 1. firstorderopt=707.1440 很奇怪,一般这一项都是等于0的吧? 2. Hessian矩阵值好象也不对,太大了. 但exitflag = 4又提示成功收敛. 所以我不太清楚问题出在哪里,想请知道的高人出来指点一下,能否看出这个优化过程可能在哪里有问题? |
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