回复: matlab曲线拟合
对于前两个问题,结果为:
fx1=b(1)*b(2)*exp(b(3)*x)./(b(2)-b(1)+b(1)*exp(b(3)*x));
SSy = 92.859
b =[0.47763211, 7.8235271, 0.034831922]
RSS = 1.697449365
MSe = 0.14145
R^2 = 0.98172
fx2=b(4)*b(1)*b(2)*exp(b(3)*(x-25))./(b(2)-b(1)+b(1)*exp(b(3)*(x-25)));
SSy = 19.657
b =[0.013595125, 3.3361276, 0.056854978, 1.1402108]
RSS = 0.07766445926
MSe = 0.0070604
R^2 = 0.99605
第3个问题
fx3=b(5)-(b(1)*b(2)*exp(b(3)*x))./(b(7)*(b(2)-b(1)+b(1)*exp(b(3)*x)))+b(1)/b(7)-b(2)*b(6)/b(3)*log((b(1)-b(2)-b(1)*exp(b(3)*x))/b(2));
的结果(时间关系,不及验证)似为:
b=[143.6218337, -0.1206944498, 0.004223585525, 5845.510552, 4567.540506, -102.7556157, 0.009232308418]
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