关于二元一次指数方程组的求解
 

程序如下：
syms x y m n
f2=exp(-1/20*x-1/20*y);
m2=int(int(f2,y,n+(m-x)/0.5,inf),x,0,m)
m3=int(int(f2,x,m,m+(n-y)/0.4),y,0,n)
m4=int(int(f2,x,m+(n-y)/0.4,inf),y,0,n)
m5=int(int(f2,y,n,n+(m-x)/0.5),x,0,m)
[m,n]=solve('70*exp(-m/20)+30*(exp(-m/20)-1)-36*20+38/20*m2-14/20*m3=0','65*exp(-m/20)+28*(exp(-m/20)-1)-36*20+35/20*m4-19/20*m5=0','m','n')

计算结果如下：
m2 =

(400*exp(m/20) - 400)/exp(m/10 + n/20)


m3 =

400/exp(m/20) + 800/(3*exp(m/20 + n/8)) - 2000/(3*exp(m/20 + n/20))


m4 =

((800*exp((3*n)/40))/3 - 800/3)/exp(m/20 + n/8)


m5 =

400/exp(n/20) + 400/exp(m/10 + n/20) - 800/exp(m/20 + n/20)


m =

z


n =

z1
请问z和z1是什么？