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【求助】请教高手如何实现几个matlab小程序的调用,谢谢
非常感谢你能打开这个帖子,我是matlab的初学者,以前在学校学过用过一下子matlab,现在基本上还给我的老师了,工作遇到了要用matlab,有些问题不懂,想让高手指点一下子,就是matlab中的小程序如何衔接调用,譬如附件中的几个matlab的程序,基本上能看懂,但是就是不知道怎么衔接起来,还有一些设定参数不知道怎么改变调整。清高手指点一下子,见笑了。谢谢。
1.稳态解程序 1.1函数wt.m〔稳态典型参数的输入) global YHY AF lIX B global UH KSB H global UAK NH KOAB A global KH global S10S SOX IOX SOX BHOX BAO0 0S NOOS NHOS ALKO %进水组分 global VQ dh dx SRT O Os %模型参数值 YH =0.71; YA =0.24; FI= 0.07; IX B=0.086; UH=5.70; KS=20.0; BH=0.48; UA=0.45; KNH=0.5; KOA=0.3; BA=o.1; KH=100; %进水划分 S10 =40; SS O=64; X1 0=40; XS O=160; XB HO=96; XB AO=0.001; SN OO=1; 00 =0; SN HO=12.5; SA LKO=6.0; %运行参数 V= 45 ; Q= 10 0; SR T= 10 ; Os =8 .6 37; 0= 2; dx =工/SR丁; dh =V /Q ; 1.2在运行wt二的基础上运行chengxu.m 数,chengxu.m如下: global YH YA FI IXB global UH KS BH global UA KNH KOA BA globalK H global S11 SSl XII XSl XBHI XBA1 Ol SNOI SNHI SALK1 global V Q dh dx Os O syms SI SS XI XS XBH XBA SNO SNH SALK Kla component0=[SISS X IX SX BHX BAK laS NOS NHS ALK]; influent=[SI] SS1 XII XSl XBHl XBAI Ol SNOI SNHI SALKI]; velocity=sym(zeros(1,10)); table=sym(zeros(5,10)); process=sym(zeros(5,1)); equation=sym(zeros(10,1)); process(1)=UH*(S S/(KS+SS))*XBH; process(2)= UA*(SNH/(KNH+SNH))*(O/(KOA+O))*XBA; process(3)=BH*XBH; process(4)=BA*XBA; process(5)=KH* XS; table(1,2)=-1/Y H ; table(1,5)=I; table( 1,7)=-(1-YH)/YH; table(1,9)=-IXB; table(1,10)=-IXB/14; table(2,6)=1; table(2,7)=-(4.57-YA)/YA; table(2,8)=1/YA; talbe(2,9)=-IXB-1/YA; table(2,10)=-IXB /14 -1/(7*YA) ; table(3,3)=FI; table(3,4)=1-FI; table(3,5)=-1; talbe(3,9)=IXB; table(4,3)=FI; table(4,4)=1-FI; table(4,6)=l; table(4,9)=IXB; table(5,2)=1; table(5,4)=-1; for i=1:10 for j= 1:5 velocity(i)=velocity(i)+table(j,i)*process(j); end end v=velocity'; equation(1,1)=influent(1)*dh-component0(1)*dh+velocity(1); equation(2,1)=influent(2)*dh-component0(2)*d h+velocity(2); equation(3,1)=influent(3)*dh-component0(3)*dx+velocity(3); equation(4,1)=influent(4)*dh-component0(4)*dx+velocity(4); equation(5,1)=influent(5)*dh-component0(5)*dx+velocity(5); equation(6,1)=influent(6)*dh-component0(6)*dx+velocity(6); equation(7,1)=influent(7)*dh+component0(7)*(Os-O)+velocity(7); equation(8,1)=influent(8)*dh-component0(8)*dh+velocity(8); equation(9,1)=influent(9)*dh-component0(9)*dh+velocity(9); equation(10,1)=influent(l0)*dh-component0(10)*dh+velocity(10); equation; Sl='x(1)'; SS='x(2)'; XI='x(3)'; XS='x(4)'; XBH='x(5)'; XBA='x(6)'; Kla='x(7)'; SNO='x(8)'; SNH='x(9)'; SALK='x(10)'; subs(equation(l,l)) subs(equation(2,1)) subs(equation(3,1)) subs(equation(4,1)) subs(equation(5,1)) subs(equation(6,1)) subs(equation(7,1)) subs(equation(8,1)) subs(equation(9,1)) subs(equation(10,1)) 1.3运行chengxu.m后,得到10个方程,组成非线性常微分方程组,用i'数rigid.m表示: %rigid.m function dx=rigid(t,x) dx=zeros(10,1) dx(1)=800/9-20/9*x(1); dx(2)=1280/9-20/9*x(2)-570/71*x (2)/(20+x(2))*x(5)+100*x(4); dx(3)=800/9-1/10*x(3)+21/625*x(5)+7/1000*x(6); dx(4)=3200/9-1001/10*x(4)+279/625*x(5)+93/1000*x(6); dx(5)=640/3-29/50*x(5)+57/10*x(2)/(20+x(2))*x(5); dx(6)=1/4 50-1/5 *x (6)+9/23* x( 9)/(1/2+x(9))*x( 6); dx(7)=6637/10 00*x(7)-1653/710*x(2)/(20+x(2))*x(5)-1299/184*x(9)/(1/2 +x(9))*x(6); dx(8)=-20/9*x(8)+75/46*x(9)/(1/2 +x(9))*x(6); dx(9)=250/9-20/9*x(9)-2451/5 000*x(2)/(20+x(2))*x(5)+43/5000*x(6); dx(10)=40/3-20/9*x(10)-2451170000*x(2)/(20+x(2))*x(5)-37887/161000*x(9)/(1/2+x(9))*x(6); 1.4 用龙格一库塔法解上面的常微分方程组, %main.m xO=[40 1.5 889 30 1450 90 150 40 [T,X]=ode45('rigid',[O 0.001],x0) 程序为main.m: 1.5 程序运行结果如下 T= 0 0.0 0 00 0.0 0 0 1 (省略) 0.0009 0.0009 0.0010 0.0010 0.0010 Oe+003* 0.0 4 00 0.0015 0.0003 0.0025 0.8890 0.0300 1.4500 0 .0900 0 .1500 0 .0400 0.0 4 00 0.0003 0.0 0 16 0.0025 0.8890 0.0300 4500 0 .0900 0 .1500 0 .0400 0.0 4 00 0.0003 0.0 0 16 0.0025 0.8890 0.0299 4500 0 .0900 0 .1500 0 .0400 0.0 4 00 0.0032 0.0003 0.0025 0.0 4 00 0 .0032 0.0003 0.0025 0.0 40 0 0 .0032 0.0003 0.0025 0.0 4 00 0 .0033 0.0003 0.0025 (省略) 0.8890 0.0282 1.4502 0 .0900 0 .1504 0 .0400 0.8890 0.0282 1.4503 0.0900 0.1504 0 .0400 0.8890 0.0281 1.4503 0.0900 0.1504 0 .0400 0.8890 0.0281 1.4503 0 .0900 0 .1504 0 .0400 118 |
其实,楼主已经写得很清楚了!
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