xiaoduan259
2008-08-13, 13:54
我不知道能不能在这里显示公式，试了一下没有得行，所以只好以附件的形式传上。本来想这样已麻烦大家了，还要下附件来看就有点不好意思了：）。不过，本人初学，而有点急于求此式值，还请大家给我指点。第一，这样求对不对？有没有可能简便？；第二，结果输出也太长了，呵呵 不晓得如何化简，其中的Struveh怎么处理？谢谢！
function lpegrowth()
a=0;c=100;b=0.1;
C1=12;Cs=0.013158;D=0.0004;K=0.01;
t=30;
x=[a:b:c];
y=besselj(3,x);
i=find(y(1 : (c-a)/b).*y(2 : (c-a)/b+1)<0);
for j=1:size(i,2) %size（i，2）
r(j) = fzero(inline('besselj(3,x)'),[x(i(j)) x(i(j)+1)]);
end
for j=1:size(i,2)
syms x t
A(j)=(int(besselj(3,x).*x,0,r(j)))/(besselj(4,r(j))).^2;
F(j)=A(j)/r(j).^2*(besselj(4,r(j)/2)+besselj(2,r(j)/2));%取l/L=1/2
sum=symsum(F(j),1,size(i,2));
h=249.85-901.6*sum；%将各参数代入化简
end
hh=simple(h)
h=
4997/20-423257136495541022704583672537678/188467143083853026902895176025*besselj(0,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))+306472754990119802/6507108870716640195622239493166121669178311875*944461883059960475298757144727590783263686620542320351641600^(1/2)*besselj(1,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))+634885704743311534056875508806517/753868572335412107611580704100*pi*(besselj(0,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))*StruveH(1,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))-besselj(1,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))*StruveH(0,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2)))
hh=
4997/20-423257136495541022704583672537678/188467143083853026902895176025*besselj(0,6905297936013695/70368744177664)+43132205786647276837666665005056/942335715419265134514475880125*besselj(1,6905297936013695/70368744177664)+634885704743311534056875508806517/753868572335412107611580704100*pi*besselj(0,6905297936013695/70368744177664)*StruveH(1,6905297936013695/70368744177664)-634885704743311534056875508806517/753868572335412107611580704100*pi*besselj(1,6905297936013695/70368744177664)*StruveH(0,6905297936013695/70368744177664)
function lpegrowth()
a=0;c=100;b=0.1;
C1=12;Cs=0.013158;D=0.0004;K=0.01;
t=30;
x=[a:b:c];
y=besselj(3,x);
i=find(y(1 : (c-a)/b).*y(2 : (c-a)/b+1)<0);
for j=1:size(i,2) %size（i，2）
r(j) = fzero(inline('besselj(3,x)'),[x(i(j)) x(i(j)+1)]);
end
for j=1:size(i,2)
syms x t
A(j)=(int(besselj(3,x).*x,0,r(j)))/(besselj(4,r(j))).^2;
F(j)=A(j)/r(j).^2*(besselj(4,r(j)/2)+besselj(2,r(j)/2));%取l/L=1/2
sum=symsum(F(j),1,size(i,2));
h=249.85-901.6*sum；%将各参数代入化简
end
hh=simple(h)
h=
4997/20-423257136495541022704583672537678/188467143083853026902895176025*besselj(0,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))+306472754990119802/6507108870716640195622239493166121669178311875*944461883059960475298757144727590783263686620542320351641600^(1/2)*besselj(1,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))+634885704743311534056875508806517/753868572335412107611580704100*pi*(besselj(0,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))*StruveH(1,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))-besselj(1,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2))*StruveH(0,1/9903520314283042199192993792*944461883059960475298757144727590783263686620542320351641600^(1/2)))
hh=
4997/20-423257136495541022704583672537678/188467143083853026902895176025*besselj(0,6905297936013695/70368744177664)+43132205786647276837666665005056/942335715419265134514475880125*besselj(1,6905297936013695/70368744177664)+634885704743311534056875508806517/753868572335412107611580704100*pi*besselj(0,6905297936013695/70368744177664)*StruveH(1,6905297936013695/70368744177664)-634885704743311534056875508806517/753868572335412107611580704100*pi*besselj(1,6905297936013695/70368744177664)*StruveH(0,6905297936013695/70368744177664)