extreme008
2013-02-26, 16:14
谁能帮忙解下这个积分啊，小弟刚接触matlab，解不出来，请大侠指点一下问题出在哪里
syms t H L m0 t1
mt=m0+2.37*t^1.29
ft=0.012*(mt/sqrt(1.0+mt))^(-12.845)
gt=3.995*mt^(-0.115)
st=gt*(H/L)^ft
int(st,t,0,t1)
这是我用matlab编的
结果如下
mt =
m0 + (237*t^(129/100))/100
ft =
3/(250*((m0 + (237*t^(129/100))/100)/(m0 + (237*t^(129/100))/100 + 1)^(1/2))^(2569/200))
gt =
799/(200*(m0 + (237*t^(129/100))/100)^(23/200))
st =
(799*(H/L)^(3/(250*((m0 + (237*t^(129/100))/100)/(m0 + (237*t^(129/100))/100 + 1)^(1/2))^(2569/200))))/(200*(m0 + (237*t^(129/100))/100)^(23/200))
Warning: Explicit integral could not be found.
ans =
int((799*(H/L)^(3/(250*((m0 + (237*t^(129/100))/100)/(m0 + (237*t^(129/100))/100 + 1)^(1/2))^(2569/200))))/(200*(m0 + (237*t^(129/100))/100)^(23/200)), t = 0..t1)
syms t H L m0 t1
mt=m0+2.37*t^1.29
ft=0.012*(mt/sqrt(1.0+mt))^(-12.845)
gt=3.995*mt^(-0.115)
st=gt*(H/L)^ft
int(st,t,0,t1)
这是我用matlab编的
结果如下
mt =
m0 + (237*t^(129/100))/100
ft =
3/(250*((m0 + (237*t^(129/100))/100)/(m0 + (237*t^(129/100))/100 + 1)^(1/2))^(2569/200))
gt =
799/(200*(m0 + (237*t^(129/100))/100)^(23/200))
st =
(799*(H/L)^(3/(250*((m0 + (237*t^(129/100))/100)/(m0 + (237*t^(129/100))/100 + 1)^(1/2))^(2569/200))))/(200*(m0 + (237*t^(129/100))/100)^(23/200))
Warning: Explicit integral could not be found.
ans =
int((799*(H/L)^(3/(250*((m0 + (237*t^(129/100))/100)/(m0 + (237*t^(129/100))/100 + 1)^(1/2))^(2569/200))))/(200*(m0 + (237*t^(129/100))/100)^(23/200)), t = 0..t1)