cqmobile_lee
2010-01-07, 15:57
请高手指导一下，搞了半天就是搞不懂呀！谢谢！
实现f（x，y）=2y;在x属于[-1,-0.8],y属于[0.8,1]的区间积分。
程序如下： syms x y
>> f = @(x,y)2*y;
>> I=dblquad(f,-1,-0.8,0.8,1);
报错如下：
??? Attempted to access y(7); index out of bounds because numel(y)=1.
Error in ==> quad at 70
if ~isfinite(y(7))
Error in ==> dblquad>innerintegral at 88
Q(i) = feval(quadf, intfcn, xmin, xmax, tol, trace, y(i), varargin{:});
Error in ==> quad at 62
y = f(x, varargin{:});
Error in ==> dblquad at 64
Q = feval(quadf, @innerintegral, ymin, ymax, tol, trace, intfcn, ...
就是不清楚错在哪里呀，请高手指点下，谢谢！
实现f（x，y）=2y;在x属于[-1,-0.8],y属于[0.8,1]的区间积分。
程序如下： syms x y
>> f = @(x,y)2*y;
>> I=dblquad(f,-1,-0.8,0.8,1);
报错如下：
??? Attempted to access y(7); index out of bounds because numel(y)=1.
Error in ==> quad at 70
if ~isfinite(y(7))
Error in ==> dblquad>innerintegral at 88
Q(i) = feval(quadf, intfcn, xmin, xmax, tol, trace, y(i), varargin{:});
Error in ==> quad at 62
y = f(x, varargin{:});
Error in ==> dblquad at 64
Q = feval(quadf, @innerintegral, ymin, ymax, tol, trace, intfcn, ...
就是不清楚错在哪里呀，请高手指点下，谢谢！